The average speed at A kelvin and the most probable speed at B kelvin of CO2
gas is 9*10^4 cm/sec. Calculate the value of A and B.
2006-12-15 16:15:41 · 4 answers · asked by Annie 1 in Science & Mathematics ➔ Chemistry
sqrt(3rt/m)
2006-12-15 16:26:20 · answer #1 · answered by santhosh 1 · 0⤊ 0⤋
E=3/2 KbT
2006-12-15 16:27:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋
R = 8.314 J/ok*mol...it is a continuing, typically used in equations. T = 298 ok or 298 Kelvin, a level of temperature. To get Kelvin, only upload your Celcius degree, therefore 23 C + 273 = 298 ok. M is the molecular weight. Oxygen is O=O and one oxygen molecule is 16 g/mol so O=O is 32 g/mol... so we ought to do the conversion to km... 32 g/mol x (1kg/1000g) = 0.032 kg/mol ...0.0319998 is a more desirable precise molecular weight... So the reply given is ideal.
2016-10-18 08:51:42 · answer #3 · answered by ? 4 · 0⤊ 0⤋
A = 1683 K
B = 2143 K
2006-12-18 07:09:37 · answer #4 · answered by g3xzx 1 · 0⤊ 0⤋