What is the probability of randomly selecting one of the shortest diagonals from among all the diagonals of a regular ocatagon?
2006-12-15 14:12:13 · 6 answers · asked by Sally 2 in Science & Mathematics ➔ Mathematics
diagonal= d
n= number of sides of polygon
d=n(n-3)/2
d=8(8-3)/2
d=8(5)/2
d=40/2
d=20
As you can see from above, there are 5 diagonals from each vertex of the octagon. When you draw the diagonals, it becomes apparent that there are:
2 short diagonals
2 medium diagonals
1 long diagonal
Because the diagonals are shared by 2 vertexes, only account for 4 vertexes
2 short diagonals x 4 vertexes = 8 short diagonals
probability= favorable outcomes/possible outcomes
probability= 8/20 => 2/5
2006-12-15 14:46:10 · answer #1 · answered by Anonymous · 0⤊ 0⤋
There are five diagonals from each vertex of an octagon. In a regular octagon, one is long, two are medium, and two are short. This means that the probability of selecting one of the shortest diagonals is 2/5.
2006-12-15 14:25:41 · answer #2 · answered by Lily 3 · 0⤊ 0⤋
octagon is eight sided figure
and it has 4 diagonals
probability of selecting one of the shortest is 1/4
2006-12-15 14:19:14 · answer #3 · answered by latha 2 · 0⤊ 0⤋
8/26= 4/13
2006-12-15 14:17:41 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
Probability the sample contain 0,1,2 defectives. .98^10 + 10*.98^9*.02 + 45*.98^8*.02^2
2016-05-22 22:30:36 · answer #5 · answered by Anonymous · 0⤊ 0⤋
1/8
since its a regular octagon...
2006-12-15 14:15:12 · answer #6 · answered by MrSmarT 3 · 0⤊ 0⤋