simplifying?

Question

9x²y 16x⁴y²
____ x ____
-4x³y⁴ 25xy


not sure what they want me to do

(sorry if that looks uneven)

Answer 1

(9x^2*y^1)/(-4x^3*y^4) * (16x^4*y^2)/(25x^1*y^1)
is what you wrote.
rewritten as all the stuff in numerator, and denominator.
(9*16*(x^2)*(x^4) *(y^1)*(y^2) )/
-4*25*(x^3)*(x^1)*(y^4)*(y^1) ).
Note the similar things in both numerator and denominator.
pay attention to make sure and ADD the number of the exponent when you multiply two of the same base.
explanation: 2^3=8=4*2=(2^2)*(2^1)=2^(2+1)=2^3.

(9*16*(x^6)*(y^3) )/( (-4)*25*(x^4)*(y^5).
note: x^1 in denominator equals X^(-1) in numerator.
likewise with y^2 in denominator equals y^(-2).
16/-4= (16/4) / (-4/4) = (4)/(-1)
9*(4)/(-1)*25 * (x^6)/(x^4) * (y^3)/(y^5) = 36/(-25) * x^2 * y^(-2) .
(36x^2 )/(-25y^2).
note: some teachers want the negative out front.

Answer 2

You can simplify some before even multiplying:

9x²y/(-4x³y⁴) = 9/(-4xy³)

and

16x⁴y²/25xy = 16x³y/25

So then

9/(-4xy³) * 16x³y/25

and then, cancelling

-36x²/25y²

It's all a matter of subtracting exponents, really.

Answer 3

9 16y
__x__
-4x 25x

-9 4y
25x
if I read the ? right, then that's the answer

Answer 4

find your common factor and factor out from the bottom and top

Answer 5

ummmmmmmm u have to be kidding me i thought fraction simplifiying

Answer 6

161x^3x^6y^3y

Answer 7

900X4Y4