it's sure starting look like she's flirtin' with me♥
2006-12-15 10:52:18 · 20 answers · asked by Anonymous in Entertainment & Music ➔ Polls & Surveys
i'm bi. Why would the name Natalie imply i'm a lesbian?
2006-12-15 10:57:00 · update #1
I think she does.....your very cute, I can understand why.....
2006-12-15 10:55:25 · answer #1 · answered by cereal_killer034 5 · 2⤊ 2⤋
Not saying don't get your hopes up but i had the same expierience and I thought he was flirting but he wasn't and that made me sad but still I said man all these cute boys and i'm going after him so just let her be and if she likes u she'll ask you out when she is ready
2006-12-15 18:57:09 · answer #2 · answered by jasmen 2 · 1⤊ 0⤋
watch whether she is actually flirtuing or if she is just being friends. sometimes the actions of a best friend can be taken as flirting. sure shes flirting? dont call her on it. don't be hard on her if or when you tell her your not interested. dont be mean at all, just stay chill.
2006-12-15 18:57:34 · answer #3 · answered by Jade Skye 2 · 1⤊ 0⤋
There you go, a match made on yahoo, P and S, I'm very happy
for you.
2006-12-15 18:57:50 · answer #4 · answered by nemesis 5 · 0⤊ 0⤋
Who?
2006-12-15 18:54:24 · answer #5 · answered by Anonymous · 2⤊ 0⤋
Um....Nope I don't think so. But I'm never sure about these things.
2006-12-15 18:56:56 · answer #6 · answered by ▒Яenée▒ 7 · 2⤊ 0⤋
It's a possibility, I suppose.
2006-12-15 18:56:27 · answer #7 · answered by dyingatwork 6 · 0⤊ 0⤋
mmm, no she has a crush on me, or maybe she likes both of us cool hey more the merrier
2006-12-15 18:55:27 · answer #8 · answered by Anonymous · 2⤊ 1⤋
I think so, maybe you, her and myself can have a menage a trois?
2006-12-16 07:18:45 · answer #9 · answered by Anonymous · 0⤊ 0⤋
Mmmmmm....., are you a ? (your name suggests so)
Aren't u sure she doesn't just want to be your friend?
2006-12-15 18:55:56 · answer #10 · answered by eltitere 1 · 0⤊ 0⤋
i dont know girl but i know someone who does
2006-12-15 19:12:31 · answer #11 · answered by la naca 6 · 0⤊ 0⤋