-6r-2s+r+3s
=-5r+s
The negative in front of the brackets changes each sign within the brackets.
2006-12-15 09:09:56
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answer #1
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answered by Anonymous
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Firstly you want to get rid of the brackets. Because there is a negative sign in front of the 2nd bracket, you change the sign of everything in that bracket. The first bracket will stay the same.
= -6r -2s +r +3s
Look at the 'r' numbers & the 's' numbers serparetly.
-6r +1r = -5r
-2s +3s= 1s
Put these together & your answer is -5r +s
2006-12-15 09:56:10
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answer #2
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answered by Just me 5
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Easiest way to get rid of the brackets first;
if you have -(- that's turns to a + AND if you have -(+ that's a -
-6r-2s+r+3s
Second step is to make the calculation with the numbers which have r and s
-5r+s
2006-12-15 09:27:27
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answer #3
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answered by Pinar 6
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Use distributive property:
-6r-2s+r+3s
Combine like terms:
-5r+s
2006-12-15 10:14:44
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answer #4
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answered by Anonymous
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Distribute -1 through the second parenthesis's values:
-6r-2s+r+3s
Add the two "r's":
-5r-2s+3s
Add the two "s's":
-5r+s
2006-12-15 09:12:50
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answer #5
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answered by Joy M 7
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-6r -2s + r + 3s
-5r +s
2006-12-15 09:11:04
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answer #6
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answered by Renaud 3
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-6r-2s+r+3s
=-6r+r-2s+3s
=-5r+s
2006-12-15 09:14:34
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answer #7
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answered by raj 7
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-6r-2s+r+3s
s-5r
2006-12-15 09:11:14
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answer #8
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answered by Anonymous
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(- 6r - 2s) - (- r - 3s)
= - 6r - 2s + r + 3s
= - 5r + s
2006-12-16 03:12:43
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answer #9
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answered by Ranna Renni 2
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(-6r - 2s) - (-r - 3s) = -6r - 2s + r + 3s = -5r + s
QED
2006-12-15 10:01:00
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answer #10
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answered by CSUFGrad2006 5
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