Sr(OH)2 + 2HNO3→
1) SrNO3 + H2O.
2) Sr(NO2)2 + 2H2O2.
3) SrH2 + HNO5.
4) Sr(NO3)2 + 2H2O.
2006-12-15 09:04:29 · 5 answers · asked by Bill J 1 in Science & Mathematics ➔ Chemistry
I think I'm gonna go with 4, Alex....
2006-12-15 09:13:41 · answer #1 · answered by ? 4 · 0⤊ 0⤋
In a neutralization reaction the H from the acid combines with the OH from the base and produces water. The first part of the base combines with the second part of the acid to make the other compound called a salt.
#1 and 4 show the water and the "strontium nitrate" salt but in #1 the formula for the strontium nitrate is wrong. Since Sr has a 2+ charge and the NO3 has only a 1- charge, you would need two NO3 radicals to make a neutral compound. That makes #4 the correct answer.
#2 and #3 are just plain wrong.
2006-12-15 12:31:57 · answer #2 · answered by The Old Professor 5 · 0⤊ 0⤋
Stoichiometrically, both sides need to be balanced (not like you don't know that), but also... you have to keep in mind that both OH groups will be plucked off the Strontium.
You also make salt and water during neutralization. So 2 & 3 are not possibilities. 4 is the answer because you're making water, and the +2 charge on Sr has been satisfied by 2 NO3 groups (-1 charge each). And it is balanced.
2006-12-15 09:15:43 · answer #3 · answered by Atello 2 · 0⤊ 0⤋
4) Sr(NO3)2 + 2H2O
2006-12-15 09:14:36 · answer #4 · answered by Erebel 2 · 0⤊ 0⤋
Its 4.
Study your common ions / oxidation states. Just one of those things you need to memorize.
2006-12-15 09:46:41 · answer #5 · answered by cipherloc 1 · 0⤊ 0⤋