multiplying by 5
7x+3=-5x
adding 5x
12x+3=0
adding -3
12x=-3
dividing by 12
x=-3/12
=-1/4
however ifthe q is 7/(5x)+3/5=-x
multiply by5x
7+3x=-5x^2
5x^2+3x+7=0
x=[-3+/-rt(9-140)]/2
imaginary roots
2006-12-15 06:04:40
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answer #1
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answered by raj 7
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Well you are clear enough, so I have to take all possibilities.
First possibility:
(7/5)x + (3/5) = -x
In this case, multiply the equation with 5 on both sides which gives you 7x + 3 = -5x
which is 7x + 5x = -3
x = -3/12 = -1/4
Now the second possibility:
[7/ (5x)] + 3/5 = -x
multiply by 5x on both sides, 7 + 3x = -5x*x
which is 5x*x + 3x + 7 = 0
Solving for x with quadratic equation results in no real integer.
Though there are other more complex interpretations of your equation, I don't want to frighten you unnecessarily. Hope this helps my dear.
2006-12-15 06:15:08
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answer #2
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answered by Manohar 2
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Add x to each side and subtract 3/5 from each side: x - 3/5 + 7/5x + 3/5 = –x + x - 3/5. That gives: 12/5x = –3/5. Now divide each side by 12/5 (or multiply by 5/12): (5/12) * (12/5) * x = (–3/5) * (5/12) and doing the multiplications: x = –3/12. Simplifying the fraction: x = –¼ or as a decimal: x = –0.25.
2006-12-15 06:06:46
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answer #3
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answered by roynburton 5
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Multiply by 5 on both sides to get rid of the fractions:
5(7/5x+3/5)=5(-x)
7x+3=-5x
Subtract 7x on both sides:
-12x=3
x=-1/4
Check:
7/5(-1/4)+3/5=-(-1/4)
-7/20+3/5=1/4
-7/20+12/20=1/4
5/20=1/4
1/4=1/4
2006-12-15 06:40:35
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answer #4
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answered by Anonymous
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X= -3/12
2006-12-15 06:07:54
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answer #5
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answered by NIK..! 5
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the answer's 19! certain how-to lower than: to make this a lot less stressful, team the x's inclusive of, for sure, their +/- warning signs: 3x - 2x + 17 + 2 now it is an equation, and in case you word no equivalent signal (=), then you actually ought to assume that if there became, your entire equation must be equivalent to 0: 3x - 2x + 17 + 2 = 0 now simplify-- use uncomplicated subtraction at the same time as coping with the variables (ignoring the x's, yet remembering to placed them ultimately result) this signifies that you ought to respond to "3-2": 1x + 19 = 0 i have been given the nineteen by using including 17 and a couple of. you presently have a "1x", yet you could get rid of the "a million", because writing down only "x" fairly potential "1x" x + 19 = 0 now to remedy it, the variable must be on one aspect, and the commonplace fee on the different aspect. do not ignore that in case you're taking a range or a variable in the course of the equivalent signal, you ought to continuously replace this is +/- signal! : x = -19 or 19 = -x now you've the answer! x is an identical as "adverse 19" or "-19" or you could study it as "adverse x is an identical as 19", it is an identical ingredient. desire this became adequate element.
2016-10-18 08:18:07
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answer #6
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answered by ? 4
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7/5x+3/5= -x multiply both sides by 5
7x+3=-5x subtract 7x from each side
3=-12x divide by -12
x=-3/12=-1/4=-.25
2006-12-15 10:49:11
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answer #7
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answered by yupchagee 7
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7/5x + 3/5 = - x
7/5x + 3/5 + x = - x + x
7/5x + x + 3/5 = 0
5(7/5x) + 5(x) + 5 (3/5) = 0
7x + 5x + 15/5 = 0
12x + 3 = 0
12x + 3 - 3 = 0 - 3
12x = - 3
12x/12 = - 3 /12
x = - 3/12
x = - 1/4
x = - 0.25
- - - - - -s-
2006-12-15 06:52:05
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answer #8
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answered by SAMUEL D 7
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Well ... Let me take a look at it ...
i) (7/5)x + 3/5 = -x
7x/5 + x = -3/5
Multiply by 5 on both sides
5 ( (7x/5) + x ) = 5 ( -3/5 )
7x + 5x = -3
8x = -3
x = -3/8
x = -0.375
Is that correct, check with your teacher and please practice more so that you don't have to post your homework on Y! Answers!
Good Luck.
2006-12-15 06:11:06
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answer #9
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answered by Octy a.k.a Octane★97 5
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7/5x + x = -3/5
7x + 5x = -3
12x = -3
x = -3/12 = -1/4
Solution: {x E R | x = -1/4}
2006-12-15 06:04:24
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answer #10
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answered by aeiou 7
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