2006-12-15 04:50:58 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Assuming integer division, the answer is one less than the divisor. In other words, 4 in your case.
If it went higher (to 5) then it would divide evenly and you would get a remainder of 0...
When you have a divisor of 5, the possible remainders are {0, 1, 2, 3, 4}. The largest remainder possible is 4.
2006-12-15 05:03:32 · answer #1 · answered by Puzzling 7 · 1⤊ 0⤋
4
2006-12-15 06:36:47 · answer #2 · answered by Nate 1 · 0⤊ 0⤋
4
2006-12-15 05:08:12 · answer #3 · answered by Ray 5 · 0⤊ 0⤋
4
2006-12-15 05:02:16 · answer #4 · answered by Renaud 3 · 0⤊ 0⤋
4
2006-12-15 04:54:46 · answer #5 · answered by Semper Fi 1 · 0⤊ 0⤋
One less than the divisor
4, if the divisor is 5
2006-12-15 04:55:02 · answer #6 · answered by Anonymous · 1⤊ 0⤋
What Is The Divisor
2016-09-29 06:49:12 · answer #7 · answered by ? 4 · 0⤊ 0⤋
It would approximate the divisor. Eg. 4.99999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999 but never equal 5. Therefore the possibilities are unlimited less than 5.
2006-12-15 04:56:22 · answer #8 · answered by Anonymous · 1⤊ 3⤋
first you know what is reminder
when we divide a number by a number then the number left or remain is called reminder.
so if we r dividing by 5 means reminder will be 1,2,3,4
so largest reminder will be simple 4 and lowest reminder will be 1
2006-12-15 05:54:55 · answer #9 · answered by anubhav2k 2 · 0⤊ 0⤋
It is 4, since every whole number is of one of these forms:
5t
5t + 1
5t + 2
5t + 3
or
5t + 4.
2006-12-15 05:12:12 · answer #10 · answered by steiner1745 7 · 0⤊ 0⤋