the flywheel of a machine has a .60 meter diameter and revlolves 260 times per minute. How many meters does a point on the outside of the flywheel rim travel in 5 minutes?
2006-12-15 03:27:15 · 4 answers · asked by Levi M 1 in Science & Mathematics ➔ Mathematics
The circumreference of the flywheel is 2 times pi times r. r is half of 0.60 meter, thus the circumreference is 0.60 times pi.
260 times a minute, thus 1300 times in 5 minutes.
1300 times 0.6 times pi results in 780 times pi, which is 2450.4422698000387259832.... which is 2450.44 meter rounded.
2006-12-15 06:37:23 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Distance = 260*.6*5/2 m = 390 m
2006-12-15 03:35:27 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 1⤋
780 X pi = 2450.44 m
2006-12-15 03:35:06 · answer #3 · answered by Anonymous · 1⤊ 0⤋
.6m x 3.14 x 250 x 5 =
2006-12-15 03:31:00 · answer #4 · answered by wind cries mary 3 · 0⤊ 1⤋