2006-12-15 01:03:07 · 5 answers · asked by norman 1 in Education & Reference ➔ Homework Help
-(19x+31)/6
2006-12-15 01:11:24 · answer #1 · answered by bongo1311 1 · 0⤊ 0⤋
You need a common denominator, in this case, 6, so change all that by multiplying the first term by 3/3 and the second term by 2/2:
[3(7x-5)/3*2] - [(2*4)(5x+2)]/(2*3)
=[(21x - 15)/6] - 8(5x+2)/6
=[(21x - 15)/6] - (40x + 16)/6
=(21x - 15 - 40x - 16)/6
=(-19x -31)/6 (you wouldn't actually have the brackets in your written answer, just -19x - 31 over 6.)
I don't know where people are getting the idea they can solve x when there is no equal sign in your question!
2006-12-15 01:11:19 · answer #2 · answered by glurpy 7 · 0⤊ 0⤋
(7x-5)/2 - 4(5x+2)/3
= 7x/2 - 5/2 -20x/3 - 8/3
= 7x/2 - 20x/3 -5/2 -8/3
=( 21x-40x)/6 - (15+16)/6
= -19x/6-31/6
= -(19x+31)/6
2006-12-15 01:44:38 · answer #3 · answered by ships 2 · 0⤊ 0⤋
x= -31/19
2006-12-15 01:11:02 · answer #4 · answered by jam 1 · 0⤊ 0⤋
(-19x-1)/6
x= -1/19
2006-12-15 01:05:32 · answer #5 · answered by Amanda 4 · 0⤊ 0⤋