THE NO 369 HAS 3 NOS --3,6,9. 3HAS NO CIRCLE IN IT,6 HAS 1 CIRCLE IN IT,9 HAS 1 CIRCLES IN IT SO TOTAL NO OF CIRCLES=2. SIMILARLY , NO 680 HAS 4 CIRCLES. THEREFORE , 680+369=4+2
=6
2006-12-14 22:43:27
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answer #1
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answered by dhruv_dshmkh 1
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if you assume all equations are true, the left side of the equations are all variables represented by numbers, the right side are answers in real numbers, that 0=0 and that variables like 567 are indicative of the appropriate number holding the place in the one, ten or hundred collumn respectively, then:
1=0
2=0
3=0
4=?
5=0
6=1
7= -9
8=2
9=10
therefore 680+369= (1 hundreds+2 tens+0 ones)+
(0 hundreds+1 tens+10 ones)=120+20=140
I think your answer is 140, but I'm probably wrong
wow, in the time it took me to type this up I and see the answers above me I now think I'm really really wrong.
2006-12-15 05:20:33
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answer #2
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answered by Captain_Karma 2
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Tanktunker is a genius.
However, your delivery of the question was horrible. To declare 1 + 1 to equal 0 means we can only assume you're using mathematical rules.
Would have been much better to have
f(1) + f(1) = 0
f(2) + f(2) = 0
because we're actually doing something to the function. In fact, we can define it to be the "loop" function L.
2006-12-15 05:10:26
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answer #3
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answered by Puggy 7
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680+369=6
It's the amount of circles in the shape of the number.
2006-12-15 05:00:47
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answer #4
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answered by Tanktunker 2
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well after starring at it forever and trying to find a pattern, i have to agree to tanktunker... the number of circles seems to fit accordingly
2006-12-15 05:39:38
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answer #5
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answered by mOnKEymAn 2
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I see several equations that are incorrect. What exactly are you expecting us to do?
2006-12-15 04:37:47
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answer #6
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answered by Northstar 7
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No idea, I'm sorry. I can't find a pattern.
2006-12-15 04:40:00
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answer #7
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answered by Dan 1
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