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1+1=0
2+2=0
3+5=0
6+8=3
8+8=4
9+7=1
11+567=1
680+369=?

thanks anyone who spend a little time on my problem

2006-12-14 20:30:50 · 7 answers · asked by Xx007 3 in Science & Mathematics Mathematics

I want the answer of : 680 + 369

2006-12-14 21:06:21 · update #1

7 answers

THE NO 369 HAS 3 NOS --3,6,9. 3HAS NO CIRCLE IN IT,6 HAS 1 CIRCLE IN IT,9 HAS 1 CIRCLES IN IT SO TOTAL NO OF CIRCLES=2. SIMILARLY , NO 680 HAS 4 CIRCLES. THEREFORE , 680+369=4+2
=6

2006-12-14 22:43:27 · answer #1 · answered by dhruv_dshmkh 1 · 0 0

if you assume all equations are true, the left side of the equations are all variables represented by numbers, the right side are answers in real numbers, that 0=0 and that variables like 567 are indicative of the appropriate number holding the place in the one, ten or hundred collumn respectively, then:
1=0
2=0
3=0
4=?
5=0
6=1
7= -9
8=2
9=10
therefore 680+369= (1 hundreds+2 tens+0 ones)+
(0 hundreds+1 tens+10 ones)=120+20=140
I think your answer is 140, but I'm probably wrong

wow, in the time it took me to type this up I and see the answers above me I now think I'm really really wrong.

2006-12-15 05:20:33 · answer #2 · answered by Captain_Karma 2 · 0 1

Tanktunker is a genius.

However, your delivery of the question was horrible. To declare 1 + 1 to equal 0 means we can only assume you're using mathematical rules.

Would have been much better to have
f(1) + f(1) = 0
f(2) + f(2) = 0

because we're actually doing something to the function. In fact, we can define it to be the "loop" function L.

2006-12-15 05:10:26 · answer #3 · answered by Puggy 7 · 0 0

680+369=6
It's the amount of circles in the shape of the number.

2006-12-15 05:00:47 · answer #4 · answered by Tanktunker 2 · 4 0

well after starring at it forever and trying to find a pattern, i have to agree to tanktunker... the number of circles seems to fit accordingly

2006-12-15 05:39:38 · answer #5 · answered by mOnKEymAn 2 · 0 0

I see several equations that are incorrect. What exactly are you expecting us to do?

2006-12-15 04:37:47 · answer #6 · answered by Northstar 7 · 0 1

No idea, I'm sorry. I can't find a pattern.

2006-12-15 04:40:00 · answer #7 · answered by Dan 1 · 0 1

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