Solve 10x^2 - 23x +12 = 0?

Answer 1

10x^2 - 23x +12 = 0
(5x-4)(2x-3) = 0
x = 0.8 or 1.5

Answer 2

10x^2-23x+12=0
sum=-23
product=120
splitting the middle term such that the sum=-23 and the
product is 120, -23=(-15)+(-8) and 120=(-15)(-8
10x^2-15x-8x+12=0
taking out the common factor
5x(2x-3)-4(2x-3)=0
(2x-3)(5x-4)=0
if the productis zero each productcan be zero
equation 2x-3=0 2x=3 or x=3/2
5x-4=0 5x=4 or x=4/5
so the solutionset={3/2,4/5)

Answer 3

10x² - 23x +12 = 0
(2x - 3)(5x - 4) = 0
2x - 3 = 0 or 5x - 4 = 0
x = 3/2 or x = 4/5

Answer 4

10x^2 - 23x + 12 = 0
10x^2 - 15x - 8x + 12 = 0
5x (2x - 3) - 4 (2x - 3) = 0
(5x - 4)(2x - 3) =0
5x -4 = 0 ...... x = 4/5
or
2x - 3 = 0 ........ x = 3/2

Answer 5

The most straightforward way to solve this is by the quadratic formula.

x = [-b +/- sqrt(b^2 - 4ac)]/2a

x = [23 +/- sqrt(529 - 4(10)(12))]/20
x = [23 +/- sqrt(529 -480)]/20
x = [23 +/- sqrt(49)]/20
x = [23 +/- 7]/20
x = (23 + 7)/20 or (23 - 7)/20
x = 30/20 or 16/20
x = 3/2 or 4/5

Answer 6

(5x-4)(2x-3) = 0

5x-4 = 0 |OR| 2x-3 = 0
5x = 4 | 2x = 3
x = 4/5 | x = 3/2
= 0.8 | = 1.5

so x = {4/5, 3/2}

as fpr how the factoring is done check this
http://answers.yahoo.com/question/index;_ylt=AtUBNFPmKbDgGEyWoeutE9bsy6IX?qid=20061214231607AAYYeQM&show=7#profile-info-58e7c50ca5a831623ca7f51e058dc238aa

hope it helped

Answer 7

h^2+10h=-21 +21 h^2+10h+21=0 (h+7 ) ( h+3 ) h+7=0 h+3=0 h=-7 h=-3 -------------------- 2x^2-7x-9=0 (2x -9 ) (x +a million ) 2x-9=0 x=-a million 2x=9 x=9/2 -------------------- 3m^2-5m=-2 3m^2-5m+2=0 (3m- 2 ) (m-a million) m=2/3 m=a million its no longer ordinary to describe a thank you to do it..

Answer 8

Quadratic formula

Answer 9

x=1.5 or x=0.8

Answer 10

1.5 or 0.8.