2006-12-14 18:45:40 · 7 answers · asked by Thomas and M 1 in Science & Mathematics ➔ Mathematics
(p + 5q) (p - 2q)
2006-12-14 18:49:14 · answer #1 · answered by feanor 7 · 0⤊ 0⤋
p^2+3q-10q^2
sum=3
product=-10
splitting the middle term such that the sum=3 and the
product is -10, 3=(+5)+(-2) and 120=(5)(-2)
p^2+5pq-2pq-10q^2
taking out the common factor
p(p+5)-2q(p+5)
(p-2q)(p+5)
2006-12-15 03:07:36 · answer #2 · answered by raj 7 · 0⤊ 1⤋
p^2 + 3pq - 10q^2
= p^2 - 2pq + 5pq - 10q^2
= p(p -2q) + 5q(p - 2q)
= (p + 5q) (p - 2q)
2006-12-15 04:30:42 · answer #3 · answered by Srinivas c 2 · 0⤊ 0⤋
p² + 3pq - 10q² = (p+5q)(p-2q)
2006-12-16 11:25:23 · answer #4 · answered by Ranna Renni 2 · 0⤊ 0⤋
(p - 2q)(p + 5q)
2006-12-15 02:55:46 · answer #5 · answered by Dan 1 · 0⤊ 0⤋
(p + 5q)(p - 2q)
2006-12-15 02:49:06 · answer #6 · answered by bkc99xx 6 · 0⤊ 0⤋
(p+5q) ( p-2q)
2006-12-15 04:01:13 · answer #7 · answered by Anonymous · 0⤊ 0⤋