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I am supposed to write y to the 7/2 power without radical exponents...
that's the root of y to the 7th. I simplified it further and wrote y cubed root y. However, on the answer sheet it's simply written as root y to the 7th power.
Is this reducable or no?

2006-12-14 17:10:08 · 3 answers · asked by Q&A Chick 2 in Science & Mathematics Mathematics

3 answers

√y = y^(1/2)

So (√y)^7 = [y^(1/2)]^7 = y^(7/2).

(√y)^7 = y^(7/2)

The two are equivalent and can't be reduced further.

2006-12-14 17:20:32 · answer #1 · answered by Northstar 7 · 1 0

y^(7/2) cannot be reduced. It might read and calculate better with a decimal exponent, y^3.5, but this is not really a simplification.

2006-12-15 01:29:13 · answer #2 · answered by Helmut 7 · 0 0

I agree with your answer. y cubed root y.

Some books and/or teachers don't expect you to simplify. I suspect that is what is going on here.

2006-12-15 01:19:47 · answer #3 · answered by huckleberry 5 · 0 0

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