(3)^k - 1 + 2∙(3)^(k+1)-1?

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this was part of my final, see who can solve it, if you give up, well the answer is 3^(k+1) +1

2006-12-14 16:59:09 · 2 answers · asked by che_karlos 2 in Science & Mathematics ➔ Mathematics

3^k-1=3^k/3 , 2*3^(k+1)=6*3^k then we have:3^k/3+6*3^k-1=(19/3)*3^k-1=19*3^(k-1)-1 .yor answer is wrong or this problem is wrong.

2006-12-16 00:28:38 · answer #1 · answered by grassu a 3 · 0⤊ 0⤋

We surrender! No idea! tell us how you’ve done this treadmill of a problem.

2006-12-15 00:10:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋