Help! multiply (x +2) by (squarerootsign( 3x^2 +8x = 7)?

Question

I knw the answer is 3x +2 + (3/x+2) but I do not know how to get there

SAMI V- no smartass, im helping my boyfriend with his homework I was in algebra 2 three years ago and therefore do not have a book to look off of- if I did you bet your *** I would look it up. Now I was asking the kind ppl of yahoo to help me out since I cannot remember for the life of me thank you very much.

And for your information, calculators only give answers in numercial form, rendering this type of problem as an error.

good day.

thanks for looking suol,

It's actually 3x^2 +8x +7

Yeah, that's what I was thinking. Absolutely no way to get his teacher's answer.

Thanks for your effort.

Answer 1

Is the square root over (3x^2 + 8x) or (3x^2 + 8x =7)? Because, I am having a hard time with the latter. Oh, ok. Well, give me a min. I might be able to help.

Well, it looks like I wont be able to help. I am sorry. If the problem is: (x+2)(sqroot(3x^2+8x+7)), I dont really see any simplification. The only help that I may be able to offer is to look at (x+2) and instead of seeing it as that look at it from a new perspective. (x+2) is the same as saying sqroot (x+2)^2. You get my drift?

Good luck.

Answer 2

I think you have to make the 3x^2+8x=7 into 3x^2+8x-49=0 (you do that by getting rid of the sq root sign by multiplying both sides of the equation which would make it a +49 and bringing that over to the other side of the = mark which would make it a -49) and use the quadratic equation to find the roots of that. Then multiply that with the x+2.

Answer 3

Have you misplaced your calculator?