English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

How do I find the slope of these few problems?

* y = 2/5 x - 8
* 4x + 2y = -6
* x = -7
* x + 1/2 y = 5
* y = x + 8
* y = 15

I've learned how to do them....but I need a little help jogging my memory. help?

2006-12-14 16:26:12 · 4 answers · asked by Sarah 4 in Science & Mathematics Mathematics

4 answers

1. m = 2/5 [y=mx+b]
2. y = -2x - 3, m = -2
3. vertical line, slope undefined.
4. y = -2x + 10, m = -2
5. m=1
6. horizontal line, slope is 0.

2006-12-14 18:52:34 · answer #1 · answered by Anonymous · 0 0

You need to put these equations into the form y=mx+b, so solve your equations in terms of y. Then, the term multiplied by x (the m term) is your slope.

Example: y=2/5x-8 slope = 2/5
Example 2: 4x + 2y = -6
Subtracting 4x from both sides gives: 2y = -6 - 4x
Then, dividing both sides through by 2,
y = -6/2 - 4/2x
Simplifying, y = -3 -2x
The slope is the term multiplied by x, so slope = -2

2006-12-15 00:32:11 · answer #2 · answered by shadowsandfog 2 · 0 0

In " slope intercept" form the slope is the number or fraction in front of the "X", but the equation must start out with "y=" or it is not in slope intercept form.

so answers are
2/5
-2
impossible
-1
15

hope that helps!

2006-12-15 00:31:36 · answer #3 · answered by 1-4-all 3 · 0 0

slope= rise/run

1. up 2 right 5

2. down 4 left 1

3. up 1 right 1 (i think)

4. down 1 left 1

5. up 1 right 1

6. none

2006-12-15 01:10:53 · answer #4 · answered by meow 2 · 0 0

fedest.com, questions and answers