y=3/4x + 2 How do you graph this equation?

Question

I know how to graph I am just having a hard time solving the equation so that I can graph it

Answer 1

It's already solved for you. It's in slope-intercept form, which means it's quite easy to graph.

The y-intercept is 2, so starting at the origin (0,0) you count up 2 squares and put a dot at (0,2).

The the slope is the "rise over the run", 3 over 4, so starting at the dot you just made, you count up 3 squares and to the right 4 squares and make another dot at (4, 5).

Then just draw the line between them.

That's why slope-intercept is the best form for graphing.

Answer 2

y = (3/4)x + 2

Note that this is in slope-intercept form, y = mx + b.
m is the slope, and b is the y-intercept.

How you would graph this is as follows;

1) Draw a dot at the y-intercept, 2. The y-intercept is where the graph crosses the y-axis, so on the up and down axis, find 2, and draw a dot there.

2) Now, the slope is defined to be "rise over run", and this is exactly what we'll use as guide to graph the line. Our slope is 3/4, so the "rise" is 3 and the "run" is 4. What you're going to do is start with the run.

With your pencil, move 4 units to the right and then stop. Do not draw a dot, but keep your positive. Now, since the rise is 3, move up three units. THAT'S where you draw your dot.

Connect the two dots with a line, and even continue past those dots and put arrows at the end of the line. This represents this graph goes on forever both ways.

That's the main technique for graphing lines; getting it in the form y = mx + b to identify the slope and y-intercept, using the y-intercept as your start point, and then using the slope's "rise over run" to graph.

In the case where your slope is negative, you have to "run" to the left instead of the right, but you would still "rise" up.

Take y = (-3/4) x + 2.

You would still move to y = 2 on the y-axis, but this time you would go left 4 and up 3, and connect the dots.

Answer 3

your y axis equals positive 2 so you would mark that on the graph. there is a real easy way to graph fractions placed in these equations. example is a/b in which you would go towards up what ever number a is and to the right of how many b is. in the case of 3/4x you would move up 3 then to the right 4 starting from the coordinate(0,2){same as y=2}. from this point you would move up 3 again and to the right 4. this should give you enough points to graph your line.

Answer 4

To graph the function, just pick points for x and plot the coordinate (x,y). For example, when x = 0, then y = (3/4)*0 +2 = 2. So your (x,y) coordinate is (0,2). When x = 4, y = (3/4)*4 + 2 = 5. So that would be (4,5).

This equation is a line. To graph it you only need two points, and then a straight line connecting them.

Answer 5

For drawing a graph of any equation, having x and y, you can put a value of x and find the value of y. Put another value of x to get another value of y and so on.
Plot these values of x and y on the graph.

Say x=0 y will be 2 one point on the graph is (0,2)
Say x=4 y will be 5 another point on the graph will be (4,5)

For linear equation two points are sufficient, plot these on graph and join them and extend them on both sides.

Answer 6

It is y=mx+b format. Were m is the slope and b is the y-intercept (the point in the line that crosses the y axis). First graph the y intercept which is (0,2). Then use your slope to find your next point slope is rise over run, so you go up four and right 4 and plot your point. Last draw your line.

Answer 7

The question suggest you DON'T know how to graph, because there's no 'solving the equation' involved.

Just fill in any (small) value for x (e.g., zero) and calculate the resulting value for y. You now have one point (x, y) on your graph.

Do that again with another value for x (e.g., four) and calculate the resulting value for y again. You now have a second point (x, y) on your graph.

Now draw a straight line through those two points, and you're done.

Answer 8

you don't need to know the value's of the integers. just go to the point 0,2 (where the line crosses the y axis) (which would be the +2 on y=3/4X+2) then, from that point rise 3 and go over 4 units

Answer 9

y-intercept is 2, so (0,2) is one point. From there move 3 units up & 4 units right, since slope, m = 3 over 4, to get second point or let x = 4 & y = 5. Two points are (0,2) & (4,5).

Answer 10

this equations in graphable form, y = mx + b

2 is the y intercept, meaning that theres a point at (0, 2) and then the slope of the line is 3/4, so you go up three and over 4