Jim had a 96 and an 82 on his first two test. What must he score on the third test be to have an average of at

Question

least 90?

Answer 1

To find an average, you add all the things together, and divide by the number of things. So, after all three of his test scores are added together, and you divide by 3, you should get an average of 90. We'll let the score on the third test be called x since we don't know it yet

(96 + 82 + x) / 3 = 90
96 + 82 + x = 3*90
96 + 82 + x = 270
178 + x = 270
x = 92

Answer 2

First things first; write down the formula for calculating the average of 3 tests. Let t1, t2, t3 be the bests. Then the average, A, is calculated by

A = (t1 + t2 + t3)/3

However, we want the average to be AT LEAST 90, so we have to change this into an inequality.

(t1 + t2 + t3)/3 >= 90

Let's plug in the values for our first two tests.

(96 + 82 + t3)/3 >= 90

Now, multiply both sides by 3, to get

96 + 82 + t3 >= 270

Simplify,

178 + t3 >= 270

And now isolate the t3

t3 >= 92

Therefore, on Jim's third test, he must score at least a 92 to get an average of at least 90.

Answer 3

ave of 90 on 3 tests means total of 270
270-96-82=92

Answer 4

average is total sore/number of test
lets call the score of the third quiz as x
so
(90+82+x)/3=90
multiplying both sides by 3 gives
90+82+x=270
solving for x
x=270-90-82
x=98
therefore he should get a score of at least 98 in order to get an average of at least 90

Answer 5

Avg score = Sum of rankings / type of rankings So his avg after the assessments is: ( 88 + sixty 9 ) / 2 His avg after 3 assessments, the position T is the fee of the third attempt: ( 88 + sixty 9 + T ) / 3 >= 80 5 we are going to evaluate it for an regularly occurring of 80 5 and assume something more effective will provide him a more effective regularly occurring (see decrease than for rationalization): ( 88 + sixty 9 + T ) / 3 = 80 5 88 + sixty 9 + T = 80 5 * 3 T = 80 5 * 3 - 88 - sixty 9 rationalization of assumption: note that if x / 3 = 80 5 then ( x + a million ) / 3 must be >= 80 5 hence it truly is sensible mathematically to in problem-free words locate what score he needs to attain 80 5, as any more effective rankings will be more effective than 80 5

Answer 6

at least 92:
(96+82+92)/3 = 90

Answer 7

(96+82+a)/3=90 he has 3 test or will have so 3 numbers divided by 3
(178+a)/3=90
(178+a)=3*90
178+a=270
a=270-178=92
On his 3rd test he has to get a 92 or higher to get an average of 90 or more.

Answer 8

Let it be x
(x+96+82)/3=90
or x+178=90*3
or x = 270-178 = 92
Jim should get 92 or more

Answer 9

92

Answer 10

actually, he needs a 92 to get to a 90 average.