Interesting chemistry problem!!!!!!!?

Question

The alcohol content of hard liquor is normally given in terms of the "proof", which is defined as twice the percentage by volume of ethanol (C2H5OH) present. Calculate the number of grams of alcohol present in 1.00 L of 75-proof gin. The density of ethanol is 0.798 g/ml.

Answer 1

1L of 75-proof gin has 375 ml ethanol (37.5% by vol).
Number of grams is 375 x 0.798 g/ml.

Answer 2

ok so you know that 75 proof = 34.5% alcohol/v
so in 1L of gin theres .345 liters or 345 mL of ethanol.
multiply that by the density and bob's your uncle, you have the grams of alcohol.