Is 7x-4y=4 parallel, perpendicular or niether to x-4y=3?

Answer 1

Find the slopes of the lines to see if they are parallel.

y = mx + b, where "m" is the slope.

In the first equation you have:

7x - 4y = 4

Rearrange to the y = mx+b format

-4y = -7x + 4

y = -7/4 x -1

So, you can see this line has a negative slope and crosses the y axis at -1

The second equation is

x - 4y = 3

Rearrange:

-4y = -x +3
y = -1/4x -3/4

This has a negative slope, intercepting at -3/4

This is neither parallel nor perpendicular. Parallel lines have the same slopes and perpendicular lines would have an opposite slope. For instance, a line perpendicular to a horizontal line (a vertical line) would have the opposite slope.

Regards,

Mysstere

Answer 2

to ensure, position both equations in y = mx + b style. 7x - 4y = 4 provides (7/4)(x) + -a million x-4y=3 provides (a million/4)(x) - 3 = y Parallel lines have a similar slope. Perpendicular lines have slopes that are adverse reciprocals. the slopes listed right here are 7/4 and a million/4, so the answer is neither.

Answer 3

They are neither. If they were parallel they would have the same slope. If they were perpendicular they would have opposite reciprocals. (like 2 and -1/2) The slopes from your two equations once you put them in y=mx+b form are x/4 and -7x/4. Therefore it is neither.

Answer 4

Parallel lines have the same slope, m1 = m2.
Perpendicular lines: m1m2 = -1.
Solve each equation for y & examine the coefficients of x, which is the slope, m, in each.

Are they equal?
Is the product equal to -1?
Or not?

Answer 5

put it in y= mx+b form


it's paralell when the mx part matches...
it's perpendicular when the two mx parts are reciprocals or opposites of each other

1/3x , and -3/1
-4/3, 3/4

Answer 6

Its a combination of both, but not really either one. Thanks