2006-12-14 12:23:09 · 6 answers · asked by Albert M 1 in Science & Mathematics ➔ Mathematics
Assuming n is a positive integer
a(1) = 2
a(2) = 9
a(3) = 28
a(4) = 65
2006-12-14 12:26:18 · answer #1 · answered by Tom :: Athier than Thou 6 · 0⤊ 0⤋
a(1) = 1^3+1 = 1+1 = 2
a(2) = 2^3+1 = 8+1 = 9
a(3) = 3^3+1 = 27+1 = 28
a(4) = 4^3+1 = 64+1 = 65
2006-12-14 12:53:33 · answer #2 · answered by Kyrix 6 · 0⤊ 0⤋
a(1) = 1^3 + 1 = 1 + 1 = 2
a(2) = 2^3 + 1 = 8 + 1 = 9
a(3) = 3^3 + 1 = 27 + 1 = 28
a(4) = 4^3 + 1 = 256 + 1 = 257
2006-12-14 12:31:02 · answer #3 · answered by euclidjr 2 · 0⤊ 0⤋
well if n starts at 1 and goes to infinity, the first 4 terms would be: 2, 9, 28, 65
2006-12-14 12:27:21 · answer #4 · answered by f21ck 3 · 0⤊ 0⤋
1(=0^3+1) , 2(=1^3+1), 9(=2^3+1), 28(=3^3+1) (And if you don't want n=0, then 65(=4^3+1))
2006-12-14 12:25:20 · answer #5 · answered by maegical 4 · 0⤊ 0⤋
2
9
28
65
2006-12-14 12:37:53 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋