[(x-7)+y] [(x-7)-y]
2006-12-14 11:50:56 · 5 answers · asked by lookitzhealthy 2 in Science & Mathematics ➔ Mathematics
First multiply through using FOIL:
First: (x - 7)(x - 7)
Outer: -y(x - 7)
Inner: y(x - 7)
Last: - y²
The outer and inner terms cancel and you get:
(x - 7)² - y²
If you recognize that you have a = x - 7, and b = y, then you might have (a + b)(a - b) which results in a difference of squares (a² - b²). Either way, you get to the same result.
(x - 7)² - y²
Finally, expand (x - 7)²
(x² - 14x + 49) - y²
2006-12-14 11:54:49 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
Difference of squares so it's (x-7)^2 - y^2
2006-12-14 19:55:12 · answer #2 · answered by Professor Maddie 4 · 0⤊ 0⤋
[(x-7)+y] [(x-7)-y] = (x-7)^2 - y^2 = x^2-14x+49 - y^2
2006-12-14 19:54:15 · answer #3 · answered by maegical 4 · 0⤊ 0⤋
[(x-7)+y] [(x-7)-y]
(x-7)^2 - y^2
x^2 - 14x +49 - y^2
2006-12-14 19:54:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋
(x^2 - 14x + 49) -y^2
I'm 90% sure. 10% is because I did it in my head :[
2006-12-14 19:54:19 · answer #5 · answered by gloves1931 2 · 0⤊ 0⤋