Brady vs. Hou or Romo vs. Atl
Fitzgerald vs Den or Booker vs Ten
This is my 1st playoff game, any insight would be appreciated
2006-12-14 11:03:55 · 6 answers · asked by Jesse19rap 4 in Sports ➔ Fantasy Sports
Brady and Fitzgerald. Brady should be able to bounce back from his terrible performance last week, and I watched Houston's D get lit up by JP Losman a few weeks back. Denver's D hasn't been doing so great of late, and I think the team feels pretty downtrodden. Leinhert has been steadily improving at QB, and James has had 2 straight 100 yard games. If he can run well again this week, it will force Denver to stick more men in the box and open up some deeper routes for Fitzgerald.
2006-12-14 11:09:25 · answer #1 · answered by waefijfaewfew 3 · 0⤊ 0⤋
Brady is a must start in all fantasy leagues. Yes Romo is doing spectacular, but after a little hicup I wouldnt dought he comes off strong this game. But there is a better chance from my perspective that Brady has the upper edge than Romo becuase of the fact he is Tom Brady. Fitzgerald will be a little confused on sunday because of Denvers d but him and Boldin are to talented to be shut-down and I suspect that one of them will have a better day and im leaning toward Fitzgerald. Booker will have a few catches for around 50 yards NOT GOOD FANTASY NUMBERS.
Brady>Romo Fitzgerald>Booker
2006-12-14 19:09:51 · answer #2 · answered by elnino_baller 2 · 0⤊ 0⤋
Romo and Fitzgerald
2006-12-14 19:12:08 · answer #3 · answered by Giorgio 1 · 0⤊ 0⤋
brady seems to be a nice starter for this week but go with romo
bookers on a roll but fitzgerald is better go with fitz
2006-12-14 19:10:03 · answer #4 · answered by vy0441 3 · 0⤊ 0⤋
definently go with romo and fitz
brady produced no stats last week and booker is to inconsistent
2006-12-14 19:07:10 · answer #5 · answered by wa_tailback2 2 · 0⤊ 0⤋
BRADY-- He'll be out to avenge last weeks disappointment.
BOOKER-- He's become Harrington's favorite and been putting up good #'s.
2006-12-14 19:12:44 · answer #6 · answered by rrhunts2 3 · 0⤊ 0⤋