(3x^3 - x^2 + x - 2) / (3x^3 - 1) ???

Question

please show your work
thanx a bunch

Answer 1

To do long division you must look at the first term of (3x^3-1) and see how many times it goes into the first term of your other equation. In this case, it only goes in once. An example of another thing this way could be...1st term is X, going into X^2, so you put X. When you multiply X and X, you get the X^2. Then subtract and it will be zero. Also, multiply the X by the rest of the equation, put those below and subtract from the original and keep dividing like so.
I don't know how helpful that was. Oh well. I tried.

Answer 2

Solving cubics is rarely easy. The idea is to factor the numerator and denominator into first order factors and cancel out the common terms.

Here is some help:
http://people.hofstra.edu/faculty/Stefan_Waner/RealWorld/tut_alg_review/framesA_5B.html

Answer 3

You have to use long division. Long division is difficult to type on here, but you'd basically start by going

----------------------------------------------
3x^3 - 1 | 3x^3 - x^2 + x - 2

And then solve it from there.