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2006-12-14 10:33:35 · 4 answers · asked by Gc 1 in Science & Mathematics Mathematics

4 answers

To solve y' for

y = cos(2x)

You first take the derivative of cos, and then the derivative of the inside (by the chain rule.

y' = -sin(2x) [2] = -2sin(2x)

2006-12-14 10:48:21 · answer #1 · answered by Puggy 7 · 0 0

-2sin(2x)

You just pull out the number inside then derive it as normal.

2006-12-14 18:36:05 · answer #2 · answered by mandos_13 4 · 0 0

-2*sin(2x) if the derivative is taken with respect to x, of course.

2006-12-14 18:35:18 · answer #3 · answered by gfmech 2 · 0 0

d[cos(2x)]/dx = -2sin(2x)

2006-12-14 18:37:02 · answer #4 · answered by Northstar 7 · 0 0

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