find the equation of the line that passes through the points (-5,0) and (10,-3)?

Answer 1

Find the slope first, or change of y divided by change of x.

change of y = -3 - 0 = -3
change of x = 10 - (-5) = 15

-3/15 = -1/5

Now plug in one of the ordered pairs into the y=mx+b formula.

0 = -1/5(-5) + b
0 = 1 + b
b = -1

Equation:
y = 1x -1
or simply y = x - 1

Answer 2

First: find the slope:

m = (second y - first y) / (second x - first x)

m = (-3 - 0)/[10-(-5)]
m = -3/(10+5)
m = -3/15 reduced to -1/5

Second: take one set of numbers and the slope and put them into the slope-intercept form. solve for the y-intercept "b."

y = mx + b

0 = (-1/5)(-5) + b
0 = 1 + b
0 – 1 = 1-1 + b
-1 = b, b = -1

Third: take the slope and y-intercept and put them into the slope-intercept formula:

y = mx + b
y = -1x/5 – 1 OR y = -x/5

Answer 3

(-5,0) and (10,-3)

slope m=(0--3)/(-5-10)=3/-15=-1/5
y=-x/5+b
0=-5/-5+b
0=1+b
b=-1
y=-x/5-1

check
-3=-10/5-1
-3=-2-1

Answer 4

the equation is

y=1/5x-1

1/5 means one fifth

Answer 5

y = mx + b
m = (y2 - y1)/(x2 - x1) = (-3 - 0)/(10 + 5) = -3/15 = -1/5
b = y - mx = 0 - (-5)*(-1/5) = -1

y = -x/5 - 1

Answer 6

give me a min