No, proofs come from definitions, not calculators. You begin with the definition of sin and show that it leads to sin30=0.5
2006-12-14 08:36:11
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answer #1
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answered by bictor717 3
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No. It is only proof that the calculator can approximate the value of sin30° to within its degree of accuracy by calculating a number of terms from the Taylor Series of sin x. The calculated value in fact is not 0.5, but rounds to 0.5
2006-12-14 16:53:43
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answer #2
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answered by Helmut 7
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ok, you asuume there is a circle with radius of 1.
then you just draw an angle of 30 degrees. then draw the projection on x axis. you ahve a right triangle. use the properyies of right tiangle and sin laws .
sin X = opposite/ hyp.
2006-12-14 16:39:51
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answer #3
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answered by alireza_ofu 2
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it's all in special triangles, man
if you'll go to the link, you'll see that 30, 60, 90 triangle will always have the sides 1, root3, and 2. sine of 30 is just 1/2 based on trig ratios
2006-12-14 16:38:27
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answer #4
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answered by (+_+) B 4
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sinus = opposite over hypothenuse.
So, if you build a triangle that has an angle of 30 degrees, you will measure the hypothenuse being twice the length of the opposite side.
Sine tables were created using Taylor series
2006-12-14 16:41:18
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answer #5
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answered by Renaud 3
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It's "proof" at the level of confidence of the calculator. Not a formal proof.
2006-12-14 16:35:23
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answer #6
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answered by yupchagee 7
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