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I have two attempts using the computer. i tried once and got in wrong. Help please.

Hydrochloric acid can dissolve solid iron according to the following reaction.
Fe(s) + 2 HCl(aq) FeCl2(aq) + H2(g)
How much HCl in grams would you need to dissolve a 3.3 g iron bar on a padlock?
____g
How much H2 would be produced by the complete reaction of the iron bar?
___g

2006-12-14 07:33:27 · 2 answers · asked by Krazyk78 1 in Science & Mathematics Chemistry

2 answers

OK

No of moles of Fe = mass / molar mass = 3.3 / 56 = 0.0589 moles

1 mole Fe reacts with 2 mole HCl
So 0.0589 mole Fe react with 2 x 0.0589 = 0.1178 mol HCl

Mass HCl = no of mol x molar mass = 0.1178 * (1 + 35.5) = 4.3g


1 mole Fe products 1 mole H2
So 0.0589 mol Fe product 0.0589 mol H2

Mass H2 = no of mol x molar mass = 0.0589 * 2 = 0.1178g

2006-12-14 07:49:31 · answer #1 · answered by claudeaf 3 · 0 0

Convert 3.3 grams Fe into moles by dividing by the atomic weight of Fe.

From the equation, 2 mol HCl are required to react with one mole Fe, so multiply number of moles of iron by 2 to get moles of HCl. Finally multiply the moles of HCl by it's molecular weight to get grams of HCl.

For the 2nd question, start with the same number of moles of Fe. Since you get 1 mol H2 for each mole of Fe, just multiply the moles of H2 by 2 (molecular weight of H2) to get grams of H2.

2006-12-14 07:50:27 · answer #2 · answered by hcbiochem 7 · 0 0

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