Help with missing numbers division word problem.. Divisor is 5 Remainder is 3?

Question

Division question:
Ones digit in the quotient is the same as tens digit in the dividend.
Sum of digits in the dividend is 17.
Divisor is 5
Remainder is 3

My daughter who is in 5th grade had this problem on her homework assignment the other night. We did come up with the answer but the teacher is saying it is wrong. We sent a note to the teacher questioning why it was wrong. She sent home explantion as to why it is wrong, but her explanation didn't make sense. Want to be sure our answer is correct before I talk to her about this. If anyone comes up with the answer please let me know.

Answer 1

First that any number that leaves remainder 3 when
divided by 5 must end in 3 or 8, since any number
divisible by 5 ends in 0 or 5.
Let's look for a 2 digit solution.
If the sum of the digits is 17, the only
possibility is 98.
So 98 divided by 5 leaves 19 with remainder 3.
and the ones digit in the quotient and
the tens digit in the dividend are both 9.
Note, however, that
this may not be the only answer!
We still must check larger numbers.
Here are the possible dividends and quotients for 3
digit numbers:
593 118
683 136
773 154
863 172
953 190
As you can see, none of these satisfies the
conditions of the problem. But 683 has
the ones place of the quotient match the
hundreds place of the dividend.
Also, no 4 digit numbers yielded a match.
Maybe that's the root of your problem with the
teacher. If you want, e-mail me
the teacher's explanation and your
work and I'll try to sort it out for you.
Good luck.
What number did you all get for the answer?
e-mail: [e-mail]

Answer 2

divisor=5 (given)
remainder=3 (given)
dividend=98 (only two possibilities for 2-digit numbers are 89 and 98)
quotient=19 (satisfies first requirement)
19*5=95 leaving a remainder of 3

Good Luck!