16(x-1)^2 + 4(y-2)^2 =16
center?
Vertices?
Foci?
Vertical or Hortizontal?
Length of Major axis?
length of Minor axis?
Minor axis intercepts?
2006-12-14 07:26:03 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
16(x - 1)² + 4(y - 2)² = 16
ie (x - 1)² + (y - 2)²/4 = 1
ie (x - 1)²/1² + (y - 2)²/2² = 1
Do you now recognise this as the canononical form of an ellipse?
Centre ≡ (1, 2)
Semi-major axis length = 2 (in vertical direction)
Semi-minor axis length = 1 (in horizontal direction)
I'll leave the rest to you now :-)
2006-12-14 07:41:14 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
write it in the form
(x-1)^2 +1/4* (y-2)^2 =1
center(1,2)
a=1
b=2
find the others by yourself
2006-12-14 15:36:07 · answer #2 · answered by iyiogrenci 6 · 0⤊ 0⤋
your center should be 1,2. all you do is set the equation = 0 and solve for x and y.
everything else, is in your BOOK.
2006-12-14 15:29:43 · answer #3 · answered by Jonathan L 2 · 0⤊ 0⤋