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no square root on the 2 just on the 3!

2006-12-14 06:43:02 · 5 answers · asked by Micki E 2 in Science & Mathematics Mathematics

5 answers

You can imagine y as the angle in a right-angled triangle to start with. sin y = opposite / hypotenuse, so suppose the opposite side of the triangle is root3, and the hypotenuse is 2.

What is the length of the other side? By Pythagoras's Theorem, it is the square root of 2² - (root3)², so it is 1.

We therefore have a right-angled triangle with one side 1, and one side 2. Sticking two copies of the triangle together gives an equilateral triangle:

2./|
./_|
1

.../\ 2
./__\
2

Therefore y = 60º is one answer. However, there is another answer for y, as sin(180-y) = sin(y), so y = 60º or 120º.

2006-12-14 06:48:43 · answer #1 · answered by Mr. Name 2 · 0 0

This means sin y = sqrt(3)/2. If you know your special angles you know that sin(pi/3) = sqrt(3)/2.

By the way SS4, pi/3 is 60° (not 30°).

2006-12-14 06:49:24 · answer #2 · answered by Anonymous · 0 0

I agree with the last person. 30 degrees or pi/3 radians

2006-12-14 06:48:46 · answer #3 · answered by SS4 7 · 0 0

60 or 120

2006-12-14 07:07:41 · answer #4 · answered by Bao L 3 · 0 0

I believe the answer is pi/3 radians.

2006-12-14 06:45:44 · answer #5 · answered by msi_cord 7 · 0 0

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