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200.0 Joules of heat is required to raise the temperature of an object sample by 3.00ºC. If the specific heat of the object is .01490 J/gºC, what is the mass of the sample in kilograms?

0.993 x 10-3 kg
4474.3 kg
4.474 kg
40.268 kg
0.067 kg


A 2.00-kg metal object requires 5020 J of heat to raise its temperature from 20.0°C to 40.0°C. What is the specific heat capacity of the metal?

126 J/(kg • °C)
106 KJ/(kg • °C)
126 cal/(kg • °C)
142 kcal(kg • °C)


1146 joules of heat is released when a 100.0 gram sample of an unknown metal cools from 95.00°C to 65.00°C. Determine the specific heat of a metal.

2006-12-14 06:37:30 · 3 answers · asked by queenpravato 1 in Science & Mathematics Chemistry

3 answers

Specific heat is 'how much heat is required to raise the temp of 1 gram 1 degree C'

So, .01490 J raises 1 g 1 C

thus 3 x .0149 = .0447 J raises 1 g 3C

since you have 200 J can raise 200/.0447 = 4474 g 3C

=4.474 kg

5020 J / (2000g * 20C) = .1255 J/gC = 1000 * .1255 J / KgC

126 J/KgC

I think you should be able to figure out the last one...

2006-12-14 06:54:51 · answer #1 · answered by Leonardo D 3 · 0 0

I'm not going to DO them FOR you. You need to know how to read a problem and use the equation that I have you earlier to figure them out. Again, the equation is:

q=mc(delta T)

So, for your last question, it says 1146 joules of heat (that's "q") is released when 100.0 gram (that's "m") ...cools from 95C to 65C. (Delta T is 95-65).
Plug those into the equation and solve for "c" (the specific heat of the metal).

Good luck..You can do the others.

2006-12-14 06:44:01 · answer #2 · answered by hcbiochem 7 · 0 0

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2016-12-30 10:04:37 · answer #3 · answered by ? 3 · 0 0

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