Can you help me with Organic Chemistry through yahho messenger or e-mail?

Question

Is for only two exercises about mechanism reactions that I need them to me done in a few hours.

I even have them online

http://answerboard.cramster.com/chemistry-topic-5-37525-0.aspx

http://answerboard.cramster.com/chemistry-topic-5-37260-0.aspx


marcelina789 is my yahoo ID

Answer 1

CH3CH3 + (CH3)3C-O-Cl ===> CH3CH2-Cl + (CH3)3C-OH
This is a free radical chain mechanism. The free radical is regenerated in the final step to continue the reaction by abstracting a proton from another ethane, CH3CH3. The dotos, "." are a little hard to see, but they're free electrons.

(CH3)3C-O-Cl + heat ===> (CH3)3C-O. + Cl.
(CH3)3C-O. + CH3CH3 ===> (CH3)3C-OH + CH3CH2.
CH3CH2 . + (CH3)3C-O-Cl ===> CH3CH2-Cl + (CH3)3C-O.

The second reaction is hard to understand, because I don't see where you get the (CH3)3C-OH at the end. I think you miscopied. The 1,4-butanediol, HOCH2CH2CH2CH2OH, gets protonated at one end by acid to form HOCH2CH2CH2CH2OH2+. The -OH on the left snakes around to bond to the CH2 on the far right, pushing off H2O. The result is a pentagon of four -CH2-'s and one >OH+ group. The >OH+ loses H+, and the result is tetrahydrofuran, a pentagon of four -CH2-'s and an O.

Answer 2

Nobody enforces such a thing, especially when they are salaried people who essentially are "at work" 24/7. They have to conduct personal business at work, and have to perform state business at home. Only the lowest and least trusted wage earner would be criticised for using a resource this way, including the phone, copier, company pens and tablets. Please, be real.