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9 answers

There is a theorem in General relativity called The "No Hair Theorem" with states that there are only three observable properties to a black hole: mass, charge, and spin. Since antimatter has positive mass, just like regular matter, it would add to the mass of the black hole in the same way. And, if the antimatter was charge neutral (whole anti-atoms), there would be no effect on that account either.

While true that it takes an infinite Length of time for anything to pass the event horizon from the perspective of an outside observer, *all* the mass of a black hole since the time of its formation consists of such forever-in-falling mass (primarily from the star of origin) and is considered part of the black hole's overall mass. The properties of such matter other than the aforementioned (like whether or not it is antimatter) are lost to the outside observer due to gravitational redshift beyond the quantum limit of observability.

2006-12-14 09:58:31 · answer #1 · answered by Dr. R 7 · 0 0

Nothing. They would form a big black hole. To physics the sign of the charge of a lepton does not matter. Well, almost. It matters for some cross sections involving neutrinos and that matters for the early universe where more matter than anti-matter was left at the end of the day. And that matters to us because we are not made of light and neutrinos. But in a black hole it does not matter. By the time matter disappears below the event horizon, the weak interaction, which is the only thing that distinguishes matter and anti-matter, has nothing to say any more. Near the singularity electromagnetic force, strong force and weak force vanish and become united with gravity to THE FORCE. And THE FORCE makes no distinction between matter and anti-matter. So while you are asking a rather interesting question, the answer is rather boring. :-)

2016-05-24 03:24:20 · answer #2 · answered by ? 4 · 0 0

Antiparticles differ from their particle counterparts only by their charge. Antimatter would be attracted by the gravitational force of the black hole just as matter would. If the black hole is made of antimatter, the antiparticles would simply be drawn into the black hole and add to its mass. Otherwise, the antimatter would still be drawn in, but would inevitably find its counterpart, collide with it, and both would be annihilated, releasing energy. Thus, the mass of the black hole would decrease, and its energy would increase. Eventually, if it loses enough mass, it would cease to be a black hole.

2006-12-15 12:44:38 · answer #3 · answered by Frank N 7 · 0 0

You can't. Because of time dilation, anything you throw at the black hole would take infinite time to reach the event horizon. To an outside observer anyways. Even if you ignore this fact, There would still be no effect outside the black hole. Any anti-matter that ran into matter would be converted to energy. Energy causes gravity also. and this energy would cause exactly the same amount of gravity as the annihalted mass would.

2006-12-14 08:13:53 · answer #4 · answered by Demiurge42 7 · 0 1

A fascinating question...

The obvious answer is that (if you had enough antimatter) you would release enormous energy as the compressed matter annihilated on contact...but the obvious answer is always suspect.

2006-12-14 05:35:27 · answer #5 · answered by blktiger@pacbell.net 6 · 0 0

assuming that it was a matter blackhole (as opposed to an antimatter one), then it would be total armageddon, and eventually it would be totally annihialated

2006-12-14 05:26:21 · answer #6 · answered by Anonymous · 0 1

Mind-boggling!

2006-12-14 05:24:33 · answer #7 · answered by Anonymous · 0 1

Become a whitehole

2006-12-14 05:33:09 · answer #8 · answered by JAMES 4 · 0 1

Why would you do that? That's crazy. You should use antimatter for something more practical. Don't just throw it away! Dang!

By the way, I'll take 2 points please.

2006-12-14 05:46:26 · answer #9 · answered by robert 3 · 0 2

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