a student has earned scores of 87,81,and 88 on the first 3 of 4 tests.?

Question

a student has earned scores of 87,81,and 88 on the first 3 of 4 tests. If the student wants an average ( arithmatic meaning) of exactly 87, what score must she earn on the fourth test?

Answer 1

(87 + 81 + 88 + X)/4 = 87

Solve for x

Answer 2

This is a simple averaging problem. Now, the standard form for an averaging question is the sum of the scores, numbers, whatever (in this case, test scored) divided by the number of times this situation occured. So, let's write your equation as that. For the first 3 tests, the student got 87, 81, and 88. So, the average is (87+81+88)/3 . That's about 85.333333. But you need to know what the fourth test score is. So we make a new equation. You don't know what the fourth score is, so let's call it x. That makes the equation (81+88+87+x)/4. remember, now the denominator is 4 because there are 4 tests. You already know that the average must be 87, so (81+88+87+x)/4=87 Multiply both sides by 4: 87+81+88+x=348 subtract out the first three scores to find that x=92.

Answer 3

The answer would be 92. The student would have to earn a 92 on the fourth test.

92+87+81+88 = 348
Divide 348 by 3 = 87

Hope this helps! Good luck!

Answer 4

You will need a 92 on the fourth test to average with 87, 81 & 88 for an overall average of 87

Answer 5

Average of 87 for 4 nos indicates a total of 87 X 4 for the 4nos.
the sum of the other three nos is 87 + 81 + 88
Therefore the fourth no
is 87 X 4 - (87 + 81 + 88) = 92

Answer 6

You will need a 92 on the next test to score exactly 87.

Answer 7

87+81+88+x=87
use the fraction line
4

(4)256+x=87(4)
use fraction line
4

Cross out the 4 by the 256 and the one that goes under the fraction line.

256+x=348
Subtract 348 from 256 and you get 92
x=92

Answer 8

92

Answer 9

92

Answer 10

92

Answer 11

92