the numbers to work with were:
100,75, 50, 25, 2, 1
a target of 947
Is it possible if so how? i'm going crazy trying to work it out even Carol Voderman failed to do it
2006-12-14 03:40:40 · 7 answers · asked by missree 5 in Science & Mathematics ➔ Mathematics
you can only use each number once
2006-12-14 03:48:51 · update #1
my nearest is 950 same as CV
2006-12-14 03:50:21 · update #2
This is not possible. The nearest is 948
75+1=76
76*25=1900
100/50=2
1900/2=950
950-2=948
2006-12-14 03:47:10 · answer #1 · answered by Anonymous · 2⤊ 1⤋
950 is the nearest I can get
75/25 = 3
2+1 = 3
3 times 3 = 9
9 times 100 = 900
plus the 50 = 950.
2006-12-14 03:50:18 · answer #2 · answered by lovethesun 3 · 0⤊ 0⤋
When dealing with these puzzles, the key is to get the hundreds first. In this case, 900. The obvious method would be 100 x 9 (but there is no way of getting a 9). So the next method is use the 75. 13 x 75 = 975 (but you can't make 13 easily). So now we try the 50. 18 x 50 = 950 but there is no easy way to make 18, so let's try the 25. 38 x 25 = 950 and that's even less promising. So the simple answer is NO, 947 cannot be made using that combination of numbers
2006-12-14 03:55:08 · answer #3 · answered by Harry Hayfield 6 · 0⤊ 3⤋
Not always possible to get to the target from the selected numbers. Closest I could get is 948.
75
+1=76
*25=1900
/2=950
100
/50=2
950
-2=948
2006-12-14 03:50:11 · answer #4 · answered by DazerUK 2 · 1⤊ 0⤋
Sorry, closest I can get is 950.
50*25 = 1250
2+1 = 3 * 100 = 300
1250 - 300 = 950.
2006-12-14 03:49:32 · answer #5 · answered by pjm81x 2 · 0⤊ 0⤋
yes the nearest is 948!!!!
2006-12-14 03:49:54 · answer #6 · answered by rosie p 2 · 0⤊ 0⤋
I cant do it and neither can my boss. If CV cant do it then I dont think its possible
2006-12-14 03:48:43 · answer #7 · answered by Lottie 2 · 2⤊ 0⤋