At noon a jogger leaves one point, running at 8 mi/h. One hour later a bicyclist leaves the same point, traveling at 20 mi/h in the opposite direction. At what time will they be 36 miles apart
2006-12-14 01:56:01 · 4 answers · asked by Vioresa M 1 in Science & Mathematics ➔ Mathematics
Equation:
(x ) + (x + 2) + (x + 4) = 201
3x + 6 = 201
3x = 210 - 6
3x = 195
x = 195 : 3
x = 65
x + 2 = 65 + 2 = 67
x + 4 = 65 + 4 = 69
Answer: The integers are: 65, 67 and 69.
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2006-12-14 08:30:49 · answer #1 · answered by aeiou 7 · 0⤊ 0⤋
Let 2x+ 1 ..= 1st .number
2x+3 = 2nd number
2x +5 = 3rd number
Sum = 6x+9
5x+9= 201
.6x= 192
x= 32
2(32)+1 = 65 = 1st number
2(32)+3= 67 = 2nd number
2(32)+5 =69 = 3rd number
r*t=d
jogger travel 8mile/hour * t hours = 8t miles
Cyclist travels 20 miles/ hour * t - 1 hours = 20t -20 miles
Sum of distances = 8t +20t --0
Thus 8t +20t -20 = 36
28t = 36
t= 36/28 hours 1 2/7 hours = approximately 1 hour and 17 minutes and 8 seconds
Thus the time would be 1:17:08 PM
2006-12-14 10:26:29 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
Anwser:
65+67+69=201
Guess:
1.4125 hours they will be 36 miles apart.
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2006-12-14 10:00:44 · answer #3 · answered by tora911 4 · 0⤊ 0⤋
Hint for the first question: The average of the three numbers = the middle number.
2006-12-14 10:00:53 · answer #4 · answered by Anonymous · 0⤊ 1⤋