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In(tan(x))

I got 1/(tan(x)(cos(x)^2)), don't know it was correct or not.

2006-12-14 01:30:10 · 4 answers · asked by daniel_hower 1 in Science & Mathematics Mathematics

4 answers

the answer is correct

2006-12-14 01:33:19 · answer #1 · answered by grassu a 3 · 0 0

The trick with solving differentials of logarithmic functions is to do it in two parts.

If you have to differentiate ln(f(x)), where f(x) is any function of x, then you can begin by replacing the function by a variable (often, we use u)

Here, we set u = tan(x)

Differential of ln(u) = (1/u) * du

change u back to tan(x)

(1/tan(x)) * d(tan(x))
You are left with finding the differential of tan(x) and multiplying through.

2006-12-14 01:47:22 · answer #2 · answered by Raymond 7 · 0 0

The way that I differentiate natural log is the following:

The "inside" function is tan(x)

The "outside" function is ln(x)

By chain rule, when the ln(x) is the outside function, the derivative is always "the derivative of the inside divided by the inside"

derivative of tan(x) divided by tan(x)

sec^2 (x) / tan(x) which written in terms of cosine is what you got.

2006-12-14 02:21:50 · answer #3 · answered by Professor Maddie 4 · 0 0

u r right

2006-12-14 01:40:59 · answer #4 · answered by Har 2 · 0 0

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