H is ordinary hydrogen, at.wts represent atomic weights.The mean atomic weight of H is 1.0080.
2006-12-13 23:16:48 · 5 answers · asked by bhargavi 2 in Science & Mathematics ➔ Chemistry
You work it out from:
1.007825x + 2.01473(1-x) = 1.0080; where x = proportion of H1.
This gives x = 0.9998, so (1-x) = proportion of H2 = 0.0002
So, you can say that H1 is 99.98% present and H2 is 0.02% present. To calculate the ratio of the two isotopes, you really need more accurate figures, but from the data you have, you can say the ratio = 0.9998/0.0002 = 4999:1 ~ approx. 5000:1
2006-12-13 23:36:40 · answer #1 · answered by JJ 7 · 0⤊ 0⤋
let x = mass1
then 1-x = mass2
x(1.007825) +(1-x)(2.01473) = 1.0080
1.00782x + 2.01473 - 2.01473x = 1.0080
-1.00691x = -1.00673
-1.00691x/-1.00691 = -1.00673/-1.00691
x= 0.999821 = 99.9821%
(1-x) = 0.0001788 = 0.0179%
ratio 1:2 = 0.999821/0.0001788= 5593:1
2006-12-14 01:21:00 · answer #2 · answered by rm 3 · 0⤊ 0⤋
hi Ducky, Hehehehehehehehehehehehehehehehehehehehe... i like this one.."the place IS GOD"!!! which will instruct those boys a element or 2..a huge vast call My chum.. a chum, poppy1 chuffed Easter My pals..save a enormously Easter Egg for Me. Lol..
2016-12-30 09:42:44 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Its just
wt(1)*x + wt(2)*(1-x) = 1.0080 solve for x (be about .99...)
2006-12-13 23:33:23 · answer #4 · answered by deflagrated 4 · 0⤊ 0⤋
according to my calculationstheir ratios are 49.9% and51.1%.check it out with our answers.
2006-12-13 23:24:32 · answer #5 · answered by abhishek j 1 · 0⤊ 0⤋