You basically want to solve
|x| = 4
In which case, your answer is x = 4 and x = -4
2006-12-13 18:10:19
·
answer #1
·
answered by Puggy 7
·
2⤊
1⤋
This depends on whether you are dealing with real numbers or complex numbers.
For real numbers, the absolute value function is defined as follows:
|x|=x if x>=0
= -x if x<0
So, if you are dealing with real numbers, and you want to solve |x|=4, then you know that either x or -x=4. So, the answers are x=4 or x=-4.
However, with complex numbers, the absolute value function is defined as;
|z|=(x^2+y^2)^(1/2), where z=x+iy.
So, if you were looking for complex numbers satisfying |z|=4, then you would have an infinite number of them-namely points lying on the circle centred at the origin with a radius of 16.
Hope this is helpful!
2006-12-16 16:15:07
·
answer #2
·
answered by friendly_220_284 2
·
0⤊
0⤋
Actually if we look at the complex numbers in form of
(1) z = a + bi
and their absolute value defined as
(2) |z| = sqrt(a^2 + b^2)
then your answer is that every complex number z = a + bi that satisfies the formula
(3) sqrt(a^2 + b^2) = 4
is the number you are looking for (including 4 and -4 which can be represented as z = 4 + 0i (a = 4, b = 0) and z = -4 + 0i (a = -4, b = 0)
And the answer would also be that it is impossible to name all the numbers thatr satisfy (3)
2006-12-14 03:26:43
·
answer #3
·
answered by N.math 2
·
2⤊
0⤋
I think this depends on what you accept . You could say that there are just two numbers, the modulus of 4 and -4. This is represented by l4l. The l l is notation for modulus and means just the magnitude of the number. However, you could include log to the base 10 of 10,000 which has a value of 4. What about the square root of 16 and 2*2? each of these has a position on the number line. I am sure there are many others.
2006-12-14 03:38:54
·
answer #4
·
answered by RATTY 7
·
0⤊
1⤋
On a number line, which numbers are 4 units from 0?
2006-12-14 02:46:15
·
answer #5
·
answered by S. B. 6
·
0⤊
0⤋
4 and -4.
2006-12-14 02:11:06
·
answer #6
·
answered by Anonymous
·
1⤊
1⤋
4 and 3.9999 (recurring nines) both equal four. Other facts about four include that it is the only number in the English language whos value equals the number of letters it has. It is also the supreme number of the universe according to Time Cube mathmatics.
2006-12-14 02:39:04
·
answer #7
·
answered by thomastalkson 2
·
0⤊
2⤋
four and negative four
all of the numbers that have an absolute value of a number would be that number, and that number but negative. I hope this helps!
2006-12-14 02:33:42
·
answer #8
·
answered by Shadow 3
·
0⤊
1⤋
4 and -4 are the easy obvious answers, but you can also go ito the complex plane.
so the easy ones there are 4i and -4i, but you can have any number of the form
ai + b as long as sqrt(a^2 + b^2) = 4
e,g 3i + sqrt(7)
easy when you have complex numbers, it means there is an infinite amount of them!!!!!!!
2006-12-14 08:47:21
·
answer #9
·
answered by Anonymous
·
0⤊
0⤋
Just 4 and -4, right?
2006-12-14 03:06:59
·
answer #10
·
answered by G K 2
·
0⤊
1⤋
its class 10 mathematics. I study in class 10.
I will answer your question-
|x| = 4
therefore, the solution set is +4 and -4
2006-12-14 03:35:35
·
answer #11
·
answered by Deranged Soul.. 2
·
0⤊
1⤋