IVERSON HAS NOT BEEN TRADED YET.
2006-12-14 09:49:33
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answer #1
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answered by smitty 7
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No one has you read by the other peoples answers. Although for El Diablo and RJW. AI + KG + Mark Madsen = JUST PLAYOFFS. They still wouldnt come out of the Western Conference. As you both are probably from Minnesota, im from Detroit and would say Dallas, San Antonio, Phoenix, OR even Denver will come out of the West. West is much stronger this year then the East and cant wait for the Playoffs to see the matchups especially in the second round.
2006-12-13 14:09:39
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answer #2
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answered by mrt3131 2
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The Miami warmth are probable the crew contained in the NBA with the LEAST possibility of having AI. Dwyane Wade and Allen Iverson honestly ought to no longer co-exist. The Celtics at the moment have the purely right possibility of having him. different communities which have achievable: Utah, Minnesota, Cleveland...you would even throw contained in the long island Knicks for good degree...you comprehend Isiah is keen to spend good money any day of the week.
2016-11-26 01:56:46
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answer #3
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answered by Anonymous
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No one yet. But it looks like Golden State Warriors or The New Yorks Knicks. From what i know the Knicks are willin to give Frye, Anf francis for Iverson and future draft pick.
2006-12-13 14:07:29
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answer #4
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answered by Junior B 2
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Los Angeles Lakers
2006-12-13 13:46:43
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answer #5
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answered by Rachmanioff 1
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He hasn't been traded yet but so far the offers look shi++y.
His salary is what's turning teams off. He's not worth 20 million dollars a year.
2006-12-13 14:13:56
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answer #6
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answered by LaissezFaire 6
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iverson has not been traded yet
2006-12-13 14:04:57
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answer #7
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answered by sweet 2
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He's still a sixer for now. I think he should be trade to Miami or Boston.
2006-12-13 13:55:36
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answer #8
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answered by Angel 3
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he hasnt yet but hopefully to the Minnesota T-wolves AI and KG equal NBA Champs
2006-12-13 13:55:57
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answer #9
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answered by RJW 5
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RJW, your math was close put not exactly right:
AI + KG + Mark Madsen = NBA Championship
2006-12-13 13:58:12
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answer #10
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answered by Anonymous
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