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Intensity level is 101 decibels at 4.91m. How far away would a person have to be for the sound to barely be audible (at the threshold of hearing).

How do I find this?

2006-12-13 13:14:26 · 3 answers · asked by Jeff H 1 in Science & Mathematics Physics

Here's the EXACT wording. I don't know the frequencies, etc:

A rock groiup is playing in a bar. Sound emerging from the door spreads uniformly in all directions. The intensity level of the music is 101 dB at a distance of 4.91m from the door. At what distance is the music just barely audible to a person with a normal threshold of hearing? Disregard absorption. Answer in units of m.

2006-12-13 13:22:57 · update #1

Threshold of hearing-
Intensity level (dB) = 0
Intensity (W/m^2) = 10^-12

2006-12-13 13:29:09 · update #2

3 answers

Find out how many decibels the threshold of hearing is. Intesity falls off at 1/(r^2) where are is the distance from the source. You know what the ratio of intensity to distance is so just plug it in to. (101/ (4.91)^2) = (Threshold of hearing) / (x^2) where x is the distance you are looking for.

2006-12-13 13:20:18 · answer #1 · answered by Anonymous · 1 0

haha, don't be silly. It depends on the frequency of the sound. Is it a High C or a Low E? you need to know the frequency, this makes a huge difference in the answer.

2006-12-13 13:18:43 · answer #2 · answered by jpferrierjr 4 · 0 0

Are we in a controlled enviornment?

2006-12-13 13:16:25 · answer #3 · answered by Dave S 3 · 0 0

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