I just don't understand this question, please help!
An object of mass 10.0 kg is released from the top of an inclined plane which makes an angle of inclination of 30.0 degrees with the horizontal. The object slides along the inclined plane. How much work is done by gravity? (Note that the instant when the object has traveled through a distance of 2.00 m is measured along the slope. The coefficient of kinetic friction between the mass and the surface is 0.200. Use g = 10.0 m/s squared):
a. 100 J
b. 20.0 J
c. 0 J
d. 10.0 J
2006-12-13 11:59:26 · 2 answers · asked by shaft0208 1 in Science & Mathematics ➔ Physics
Work (joules) = F * D
F = ma
m = 10kg
a = 10(sin(30)) = 5m/s2
D = 2 m
Work = 50 * 2 = 100 J
The answer is A.
2006-12-13 12:13:00 · answer #1 · answered by jpferrierjr 4 · 0⤊ 0⤋
sin30=height/2
height=1m
mgh=10X10X 1
=100J
My answer is a.100J.
2006-12-13 12:06:05 · answer #2 · answered by A 150 Days Of Flood 4 · 0⤊ 0⤋