What is th equation for gravitational force and what do the variables stand for?

Question

i think it's


Gravitational force= Gm1m2 divided by r squared


but I have no Idea what it stands for so pleas help me out
and tell me what Gm1,m2,andrsquared is, and possibly why it's that way
thanx

Answer 1

G is the gravitational constant 6.673 x 10^-11

m1 and m2 are any two masses in the universe.

r is the distance between them.

The whole equation gives the force due to gravity between any two masses in the universe at a distance r.

This equation was formulated by Isaac Newton - it predicts the effects of gravity but does not explain them.

To understand gravity better you need to read some Einstein and his general theory of relativity.

Answer 2

G= gravitational constant
M1= mass of first object
M2= mass of second object
r= distance between the two objects

it's made this way because there is a gravitational constant for every gram of matter. Don't ask me the gravitational constant cause it's been years since I last used this equation. r is used also because the further away the second object is from a mass the less gravitational force there is on the second object.

Answer 3

This is easy. M1 and m2 are the two objects involved, for example, the earth and the moon. r is the distance between the two objects. You have to square that number when you do the problem. Big G in the numerator is the gravitational constant. You can find it on the reference table. You multiple everything in the numerator by it to make everything come out right.

Answer 4

Under normal earth-bound conditions, when objects move owing to a constant gravitational force a set of kinematical and dynamical equations describe the resultant trajectories. For example, Newton’s law of gravitation simplifies to F = mg, where m is the mass of the body. This assumption is reasonable for objects falling to earth over the relatively short vertical distances of our everyday experience, but is very much untrue over larger distances, such as spacecraft trajectories, because the acceleration far from the surface of the Earth will not in general be g. A further example is the expression that we use for the calculation of potential energy P.E. of a body at height h ( P.E. = mgh). This expression can be used only over small distances h from the Earth. Similarly the expression for the maximum height reached by a vertically projected body, h = u2 / 2g is useful for small heights and small initial velocities only. In case of large initial velocities we have to use the principle of conservation of energy to find the maximum height reached.

Answer 5

g probably stands for gravity

m1 is probly measurement 1

anyway gravity is ALWAYS 9.8 meters / second squared

or 32 feet per second squared

Answer 6

I know I know
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