How old is Daniel Radcliffe now? How about Rupert, and Emma? Does anybody know how to open the secret door when you click the eraser on J.K.'s website? Please help!!!!
2006-12-13 10:13:14 · 9 answers · asked by Anonymous in Arts & Humanities ➔ Books & Authors
Daniel Radcliffe is 17 years old.
Rupert Grint is 18 years old.
Emma Watson is 16 years old.
You can't open the secret door now, only when the do not disturb sign goes away. When the sign is gone there are certain instructions/steps you must follow to open it but they are different on each occasion that the door has been unlocked.
2006-12-13 10:40:11 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Daniel is 17 now. I'm not for sure on Rupert and Emma but I believe that Rupert is the oldest and Emma the youngest of the three. I don't know about the secret door. It's been awhile since I've been on her website. Sorry.
2006-12-13 18:16:24 · answer #2 · answered by Lisa 1 · 0⤊ 0⤋
According to the year of birth, Emma's 16, Daniel's 17 while Ron's 18.
2006-12-16 11:23:26 · answer #3 · answered by Charlotte_T 2 · 0⤊ 0⤋
daniel was born in the year 89which makes him 17.rupert 88which makes him 18 and emma 90 then she is 16 years old.
about the door.. there is a no disturb sign so we are not allowed to enter.
2006-12-13 18:32:58 · answer #4 · answered by JD Potter 1 · 0⤊ 0⤋
daniel is seventeen. rupert is 18. emma is 16.
2006-12-16 11:01:15 · answer #5 · answered by blah 4 · 0⤊ 0⤋
I don't remember the eraser being there the last time I visited. I guess just check back later. The eraser is a PortKey. Maybe it's in progress now.
2006-12-13 18:26:37 · answer #6 · answered by patience3987 4 · 0⤊ 0⤋
go to Internetmoviedatabase.com to look up their ages and i think the door is closed
2006-12-13 18:15:59 · answer #7 · answered by Karen Smith 3 · 0⤊ 0⤋
daniel is 17.the wed site is www.the-leaky-cauldron.org.
2006-12-13 20:01:03 · answer #8 · answered by Justmais19 3 · 0⤊ 0⤋
i have no clue but i cannot wait for the next book (or movie)
2006-12-13 18:17:35 · answer #9 · answered by Anonymous · 0⤊ 0⤋