>Algebra 1 Help<?

Question

Can somebody please show me the steps to figure this problem out? (I dont get it at all.)

Thanks

Here it is:
Suppose it takes you and a friend 3.2 hours to canoe 12 miles downstream (with the current). During the return trip, it takes you and your friend 4.8 hours to paddle upstream (against the current) to the original starting point. Find the average paddling speed in still water of you and your friend and the average speed of the current of the river. Round answers to the nearest tenth.

Answer 1

The average paddling speed in still water can be calculated by dividing the total distance travelled by the total time travelled. You can do this because the current is constant in both directions. So the average paddling speed is

(12 * 2) / (3.2 + 4.8)
24 miles / 8 hours = 3 miles per hour

The previous commentor's answer is inaccurate. If you were to multiply 3.125 MPH times 8 hours, you would get 25 miles travelled.

To calculate the average speed of the current, let's find out how long it would take for the two people to travel one direction in still water.

12 Miles / 3 MPH = 4 hours

Because it would normally take 4 hours to travel 12 miles and you saved 0.8 hours, you can divide 12 miles by 0.8 hours to calculate the speed of the current.

12 miles / 0.8 hours = 15 miles per hour

Answer 2

12/3.2 = 3.75
you use 12 again because it's the same length 12/4.8=2.5
to find the average= (3.75+2.5)/2= 3.125
you divide by 2 becasue there are 2 numbers
so the average speed is 3.125

Answer 3

3x^2 + 9x - 12 = 0 element out a three 3(x^2 + 3x - 4) = 0 3(x+4)(x-a million) = 0 one in each and every of the two numbers could desire to be equivalent to 0 x+4 = 0; x = -4 x-a million = 0; x=a million those are your 2 solutions! solid success - M

Answer 4

rate times time equals distance... remember rt=d