Escape velocity is the speed of light at the event horizon of a black hole?

Question

Im not talking about any distance to either side but right at the event horizon. Is escape velocity the speed of light right there?

Answer 1

I'd say it is very close to, but an infinitely small amount more, than the speed of light. Here's why: Escape velocity is where the speed is enough to escape the gravitation. The event horizon is where light is trapped; not falling into the black hole but also not escaping it.

Answer 2

Black hole's escape velocity is greater than the speed of light Escape Velocity According to Newton, the greater the gravity, the faster an object must go to escape into space. This is called the escape velocity. The escape velocity from any body depends on its mass, and on the starting distance. The escape velocity is larger for larger mass and smaller distance. Escape velocity = 300,000 km/s = speed of light If the Earth is compressed any more, the escape velocity would be greater than the speed of light. So nothing could escape its surface, not even light. This is the definition of a black hole. The radius at which the escape velocity is greater than the speed of light is called the event horizon. Anything inside of the event horizon will never return to our universe. This is the point of no return.

Answer 3

Right at the event horizon is where the escape velocity is the speed of light (the event horizon depends on the mass of the object I don't know why some people here seem to think this has nothing to do wit escape velocity the closer you are and the more massive the object the greater the escape velocity). From here nothing can escape, if the speed of light really is the fastest you can go, then there is no speed you can go greater than the escape velocity and therefore no way to escape!

Answer 4

Yes. In fact, if you do the Newtonian computation for the escape velocity and set it equal to the velocity of light, you can solve for the radius of the event horizon.

It is important to be very careful when dealing with general relativity, though. A person 'at infinity' will see light at the event horizon as stationary even though a person at the event horizon will see it going the speed of light. Unlike in special relativity, it is important to know where a person is as well as how fast they are moving if you want to compare measurements.

Answer 5

The escape velocity at the event horizon is by definition, the speed of light

Answer 6

No, that is not correct. Remember, the speed of light is always constant - it does not fluctuate based upon where you are located. Escape velocity is the velocity required for an object to free itself from the gravitational field of another object. In a black hole, the density is so great that even light can not escape it. The event horizon is the location at which light can no longer escape from the black hole.

Answer 7

Yes right at the event horizon.
The event horizon is very thin maybe less than a millimeter.

Answer 8

Quantum of light is a privileged particle.
Only the speed of a light quantum has
a maximal, constant, absolute quantity of c=1.
No other particle can travel with the speed c = 1.
If quantum of light flies always rectilinearly c=1, it is a mad one.
Is he really mad?
* * *
Only a light quantum has the absolute speed c=1.
No other particle can travel with the speed c = 1.
Other particle can travel only with the speed v=s/t.
And I was taught at school from the first class:
that the incommensurable quantities cannot be compared.
To connect incommensurable quantities it
is similar to the decision of a problem:
“What will be if the whale will attacks the elephant?”
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Quantum of light have two kinds of spins,
as a result of which the particle attains motion.
1)
Under the action of Planck,s spin, which is equal to the unit ( h =1)
aquantum of light flies rectilinearly with speed (c = 1).
The geometrical form of a circle: (C/D = 3,14).
A quantum of light behaves as a particle.
2)
Under the action of Goudsmit-Uhlenbeck's spin, ( ħ = h / 2pi)
a quantum of light rotates around of its diameter
with the speed more of light quanta : c>1
and is known as electron.
The geometrical form of a circle is transformed into a sphere.
This kind of movement is described by Lorentz's transformations .
The wave properties of light quantum are shown.
The dualism of a particle becomes clear.
The paradox of dualism disappears completely.
When the form of a circle is change into the form of a sphere,
the transcendental magnitude (pi = 3,14) is change
on another transcendental magnitude (е = 2,71).
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http://www.socratus.com
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Answer 9

If I understand it right, it would need to be just FTL at the event horizon because at the SOL is where the event horizon begins.

Answer 10

Yes