2006-12-13 05:40:38 · 18 answers · asked by aniscric 2 in Sports ➔ Cricket
At such a form, he can soon reach it surpassing all.
Since 2004, in all 15 centuries hit by him.
2006-12-13 22:27:07 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Looking at the hunger and the consistency of scoring centuries after centuries in test series Ponting is the only batsman capable of maintaining the pace and achieving more than 45 centuries in tests in 5 years.
2006-12-13 12:48:14 · answer #2 · answered by inderjeet d 2 · 0⤊ 0⤋
Definitely Ricky Ponting will hit 50centuries in Tests.
2006-12-13 23:30:42 · answer #3 · answered by Fun 2 · 0⤊ 0⤋
Its not a question of will he make 40 test centuries but when will he
2006-12-13 10:33:22 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Ponting currently has 33 centuries, so he would need another 7.
Barring injuries, I believe in the form he is in, he will have another 5 years in the game. I have looked up stats to see centuries per year since 2002.
2002 - 5
2003 - 6
2005 - 6
2006 - 7
So since 2002 he has 24 centuries in 5 years (including 0 in 2004).
My predictions -
1 more in 2006
2007 - 4
2008 - 6
2009 - 6
2010 - 4
2011 - 2
That would mean he would have 40 make another 22 in total, giving him 54 for his career.
2006-12-13 06:21:41 · answer #5 · answered by backpacka 4 · 1⤊ 1⤋
If he continues in his present form, he will defenitely score 40 centuries.
2006-12-13 17:11:59 · answer #6 · answered by vakayil k 7 · 0⤊ 0⤋
yes i think he is at 33-34 right now and hes 30 now something like that so i think he'll get 40 by the time he is 33-34
2006-12-13 08:18:37 · answer #7 · answered by moaiz 2 · 0⤊ 0⤋
i dont think so any batsmen would beat 40 test centuries .
2006-12-13 10:02:35 · answer #8 · answered by faizan 2 · 0⤊ 0⤋
There are three people who can reach that in the order of possibility.
1. SACHIN TENDULKAR
2. RICKY PONTING
3. BRIAN LAURA
2006-12-13 05:43:50 · answer #9 · answered by Eyedoc 4 · 0⤊ 0⤋
YES HE MAY GO FOR EVEN MORE THAN 40.
2006-12-15 01:13:33 · answer #10 · answered by RAMAN IOBIAN 7 · 0⤊ 0⤋