problem on nuclear fission ? help plzzzzzzzzzzz?

Question

how much energy wud be released on complete fission of 1Kg of uranium-235 when i fission releases energy =3.2*10^-11 joules !!!!!!!

i mean 1 fission releases energy = 3.2*10^ -11 joules

Answer 1

It is k=3.2*10^-11 joules per atom
And how many atom do we have in 1 kg of Uranium 235?

Avogadro's number (A) is 6.022 x 10^23 suggests the number of atoms per gram-mole (g-m).
So energy released is
E=A k m / (g-m)

E=(6.022 x 10^23 atoms/mole)(3.2*10^-11j/atom) (1000g)/(235g/mole)=
E=82,001,702,127,660
E=82 x 10^12 joules

Keep in mind that we assumed 100% fission.

Answer 2

You clearly made this question up. It has no answer because it has no basis in science. U238 does not necessarily split into equal halves when fission occurs. In fact, it may split into more than two parts. Second, the fissioned parts are not a "pair of molecules," they are still atoms. Third, the fissioned parts are not bound to each other in any way; so there is no "net force" between them. Perhaps what you are looking for is the energy produced when U238 fissions. That comes from good old E = mc^2. In fact, the REAL equation is E = delm c^2, where delm is the difference (del) between the U238 mass m0 before fissioning and the sum of the masses (Sum m) of the parts after fissioning. That is, del m = m0 - Sum m. What we find is that Sum m < m0; that is, some of the mass m0 is lost so the sum of the masses after splitting is less than what the U238 started with. What happened to that lost mass...it became energy...E = delm c^2. When billions and billions of U238 atoms do this, we have nuclear power plants or, if the splitting happens more rapidly...the atomic bomb.

Answer 3

ya edward is right